50x^2+5x-3=(10x+3)

Solution for 50x^2+5x-3=(10x+3) equation:

50x^2+5x-3=(10x+3)

We move all terms to the left:

50x^2+5x-3-((10x+3))=0


We calculate terms in parentheses: -((10x+3)), so:

(10x+3)

We get rid of parentheses

10x+3

Back to the equation:

-(10x+3)


We get rid of parentheses

50x^2+5x-10x-3-3=0

We add all the numbers together, and all the variables

50x^2-5x-6=0

a = 50; b = -5; c = -6;
Δ = b2-4ac
Δ = -52-4·50·(-6)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-35}{2*50}=\frac{-30}{100}
=-3/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+35}{2*50}=\frac{40}{100}
=2/5
$